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Java Solution for LeetCode algorithm problems, continually updating
1496\. Path Crossing
Easy
Given a string `path`, where `path[i] = 'N'`, `'S'`, `'E'` or `'W'`, each representing moving one unit north, south, east, or west, respectively. You start at the origin `(0, 0)` on a 2D plane and walk on the path specified by `path`.
Return `true` _if the path crosses itself at any point, that is, if at any time you are on a location you have previously visited_. Return `false` otherwise.
**Example 1:**
![](https://assets.leetcode.com/uploads/2020/06/10/screen-shot-2020-06-10-at-123929-pm.png)
**Input:** path = "NES"
**Output:** false
**Explanation:** Notice that the path doesn't cross any point more than once.
**Example 2:**
![](https://assets.leetcode.com/uploads/2020/06/10/screen-shot-2020-06-10-at-123843-pm.png)
**Input:** path = "NESWW"
**Output:** true
**Explanation:** Notice that the path visits the origin twice.
**Constraints:**
* 1 <= path.length <= 104
* `path[i]` is either `'N'`, `'S'`, `'E'`, or `'W'`.