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Java Solution for LeetCode algorithm problems, continually updating
2276\. Count Integers in Intervals
Hard
Given an **empty** set of intervals, implement a data structure that can:
* **Add** an interval to the set of intervals.
* **Count** the number of integers that are present in **at least one** interval.
Implement the `CountIntervals` class:
* `CountIntervals()` Initializes the object with an empty set of intervals.
* `void add(int left, int right)` Adds the interval `[left, right]` to the set of intervals.
* `int count()` Returns the number of integers that are present in **at least one** interval.
**Note** that an interval `[left, right]` denotes all the integers `x` where `left <= x <= right`.
**Example 1:**
**Input**
["CountIntervals", "add", "add", "count", "add", "count"]
[[], [2, 3], [7, 10], [], [5, 8], []]
**Output:** [null, null, null, 6, null, 8]
**Explanation:**
CountIntervals countIntervals = new CountIntervals(); // initialize the object with an empty set of intervals.
countIntervals.add(2, 3); // add [2, 3] to the set of intervals.
countIntervals.add(7, 10); // add [7, 10] to the set of intervals.
countIntervals.count(); // return 6
// the integers 2 and 3 are present in the interval [2, 3].
// the integers 7, 8, 9, and 10 are present in the interval [7, 10].
countIntervals.add(5, 8); // add [5, 8] to the set of intervals.
countIntervals.count(); // return 8
// the integers 2 and 3 are present in the interval [2, 3].
// the integers 5 and 6 are present in the interval [5, 8].
// the integers 7 and 8 are present in the intervals [5, 8] and [7, 10].
// the integers 9 and 10 are present in the interval [7, 10].
**Constraints:**
* 1 <= left <= right <= 109
* At most 105
calls **in total** will be made to `add` and `count`.
* At least **one** call will be made to `count`.