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Java Solution for LeetCode algorithm problems, continually updating
2315\. Count Asterisks
Easy
You are given a string `s`, where every **two** consecutive vertical bars `'|'` are grouped into a **pair**. In other words, the 1st and 2nd `'|'` make a pair, the 3rd and 4th `'|'` make a pair, and so forth.
Return _the number of_ `'*'` _in_ `s`_, **excluding** the_ `'*'` _between each pair of_ `'|'`.
**Note** that each `'|'` will belong to **exactly** one pair.
**Example 1:**
**Input:** s = "l|\*e\*et|c\*\*o|\*de|"
**Output:** 2
**Explanation:** The considered characters are underlined: "l|\*e\*et|c\*\*o|\*de|".
The characters between the first and second '|' are excluded from the answer.
Also, the characters between the third and fourth '|' are excluded from the answer. There are 2 asterisks considered. Therefore, we return 2.
**Example 2:**
**Input:** s = "iamprogrammer"
**Output:** 0
**Explanation:** In this example, there are no asterisks in s. Therefore, we return 0.
**Example 3:**
**Input:** s = "yo|uar|e\*\*|b|e\*\*\*au|tifu|l"
**Output:** 5
**Explanation:** The considered characters are underlined: "yo|uar|e\*\*|b|e\*\*\*au|tifu|l".
There are 5 asterisks considered. Therefore, we return 5.
**Constraints:**
* `1 <= s.length <= 1000`
* `s` consists of lowercase English letters, vertical bars `'|'`, and asterisks `'*'`.
* `s` contains an **even** number of vertical bars `'|'`.