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Java Solution for LeetCode algorithm problems, continually updating
2325\. Decode the Message
Easy
You are given the strings `key` and `message`, which represent a cipher key and a secret message, respectively. The steps to decode `message` are as follows:
1. Use the **first** appearance of all 26 lowercase English letters in `key` as the **order** of the substitution table.
2. Align the substitution table with the regular English alphabet.
3. Each letter in `message` is then **substituted** using the table.
4. Spaces `' '` are transformed to themselves.
* For example, given key = "**hap**p**y** **bo**y"
(actual key would have **at least one** instance of each letter in the alphabet), we have the partial substitution table of (`'h' -> 'a'`, `'a' -> 'b'`, `'p' -> 'c'`, `'y' -> 'd'`, `'b' -> 'e'`, `'o' -> 'f'`).
Return _the decoded message_.
**Example 1:**
![](https://assets.leetcode.com/uploads/2022/05/08/ex1new4.jpg)
**Input:** key = "the quick brown fox jumps over the lazy dog", message = "vkbs bs t suepuv"
**Output:** "this is a secret"
**Explanation:** The diagram above shows the substitution table.
It is obtained by taking the first appearance of each letter in "**the** **quick** **brown** **f**o**x** **j**u**mps** o**v**er the **lazy** **d**o**g**".
**Example 2:**
![](https://assets.leetcode.com/uploads/2022/05/08/ex2new.jpg)
**Input:** key = "eljuxhpwnyrdgtqkviszcfmabo", message = "zwx hnfx lqantp mnoeius ycgk vcnjrdb"
**Output:** "the five boxing wizards jump quickly"
**Explanation:** The diagram above shows the substitution table.
It is obtained by taking the first appearance of each letter in "**eljuxhpwnyrdgtqkviszcfmabo**".
**Constraints:**
* `26 <= key.length <= 2000`
* `key` consists of lowercase English letters and `' '`.
* `key` contains every letter in the English alphabet (`'a'` to `'z'`) **at least once**.
* `1 <= message.length <= 2000`
* `message` consists of lowercase English letters and `' '`.