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Java Solution for LeetCode algorithm problems, continually updating
2331\. Evaluate Boolean Binary Tree
Easy
You are given the `root` of a **full binary tree** with the following properties:
* **Leaf nodes** have either the value `0` or `1`, where `0` represents `False` and `1` represents `True`.
* **Non-leaf nodes** have either the value `2` or `3`, where `2` represents the boolean `OR` and `3` represents the boolean `AND`.
The **evaluation** of a node is as follows:
* If the node is a leaf node, the evaluation is the **value** of the node, i.e. `True` or `False`.
* Otherwise, **evaluate** the node's two children and **apply** the boolean operation of its value with the children's evaluations.
Return _the boolean result of **evaluating** the_ `root` _node._
A **full binary tree** is a binary tree where each node has either `0` or `2` children.
A **leaf node** is a node that has zero children.
**Example 1:**
![](https://assets.leetcode.com/uploads/2022/05/16/example1drawio1.png)
**Input:** root = [2,1,3,null,null,0,1]
**Output:** true
**Explanation:** The above diagram illustrates the evaluation process.
The AND node evaluates to False AND True = False.
The OR node evaluates to True OR False = True.
The root node evaluates to True, so we return true.
**Example 2:**
**Input:** root = [0]
**Output:** false
**Explanation:** The root node is a leaf node and it evaluates to false, so we return false.
**Constraints:**
* The number of nodes in the tree is in the range `[1, 1000]`.
* `0 <= Node.val <= 3`
* Every node has either `0` or `2` children.
* Leaf nodes have a value of `0` or `1`.
* Non-leaf nodes have a value of `2` or `3`.