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g0401_0500.s0450_delete_node_in_a_bst.readme.md Maven / Gradle / Ivy

450\. Delete Node in a BST

Medium

Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST.

Basically, the deletion can be divided into two stages:

1.  Search for a node to remove.
2.  If the node is found, delete the node.

**Example 1:**

![](https://assets.leetcode.com/uploads/2020/09/04/del_node_1.jpg)

**Input:** root = [5,3,6,2,4,null,7], key = 3

**Output:** [5,4,6,2,null,null,7]

**Explanation:**

    Given key to delete is 3. So we find the node with value 3 and delete it.
    One valid answer is [5,4,6,2,null,null,7], shown in the above BST.
    Please notice that another valid answer is [5,2,6,null,4,null,7] and it's also accepted.
![](https://assets.leetcode.com/uploads/2020/09/04/del_node_supp.jpg)

**Example 2:**

**Input:** root = [5,3,6,2,4,null,7], key = 0

**Output:** [5,3,6,2,4,null,7]

**Explanation:** The tree does not contain a node with value = 0.

**Example 3:**

**Input:** root = [], key = 0

**Output:** []

**Constraints:**

*   The number of nodes in the tree is in the range [0, 104].
*   -105 <= Node.val <= 105
*   Each node has a **unique** value.
*   `root` is a valid binary search tree.
*   -105 <= key <= 105

**Follow up:** Could you solve it with time complexity `O(height of tree)`?