• Home
• com.github.javadev
• leetcode-in-java17
• 1.22
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g1601_1700.s1652_defuse_the_bomb.readme.md Maven / Gradle / Ivy

1652\. Defuse the Bomb

Easy

You have a bomb to defuse, and your time is running out! Your informer will provide you with a **circular** array `code` of length of `n` and a key `k`.

To decrypt the code, you must replace every number. All the numbers are replaced **simultaneously**.

*   If `k > 0`, replace the ith number with the sum of the **next** `k` numbers.
*   If `k < 0`, replace the ith number with the sum of the **previous** `k` numbers.
*   If `k == 0`, replace the ith number with `0`.

As `code` is circular, the next element of `code[n-1]` is `code[0]`, and the previous element of `code[0]` is `code[n-1]`.

Given the **circular** array `code` and an integer key `k`, return _the decrypted code to defuse the bomb_!

**Example 1:**

**Input:** code = [5,7,1,4], k = 3

**Output:** [12,10,16,13]

**Explanation:** Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.

**Example 2:**

**Input:** code = [1,2,3,4], k = 0

**Output:** [0,0,0,0]

**Explanation:** When k is zero, the numbers are replaced by 0.

**Example 3:**

**Input:** code = [2,4,9,3], k = -2

**Output:** [12,5,6,13]

**Explanation:** The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the **previous** numbers.

**Constraints:**

*   `n == code.length`
*   `1 <= n <= 100`
*   `1 <= code[i] <= 100`
*   `-(n - 1) <= k <= n - 1`