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Java Solution for LeetCode algorithm problems, continually updating
495\. Teemo Attacking
Easy
Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly `duration` seconds. More formally, an attack at second `t` will mean Ashe is poisoned during the **inclusive** time interval `[t, t + duration - 1]`. If Teemo attacks again **before** the poison effect ends, the timer for it is **reset**, and the poison effect will end `duration` seconds after the new attack.
You are given a **non-decreasing** integer array `timeSeries`, where `timeSeries[i]` denotes that Teemo attacks Ashe at second `timeSeries[i]`, and an integer `duration`.
Return _the **total** number of seconds that Ashe is poisoned_.
**Example 1:**
**Input:** timeSeries = [1,4], duration = 2
**Output:** 4
**Explanation:** Teemo's attacks on Ashe go as follows: - At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. - At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
**Example 2:**
**Input:** timeSeries = [1,2], duration = 2
**Output:** 3
**Explanation:**
Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
**Constraints:**
* 1 <= timeSeries.length <= 104
* 0 <= timeSeries[i], duration <= 107
* `timeSeries` is sorted in **non-decreasing** order.