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g0601_0700.s0606_construct_string_from_binary_tree.readme.md Maven / Gradle / Ivy

606\. Construct String from Binary Tree

Easy

Given the `root` of a binary tree, construct a string consisting of parenthesis and integers from a binary tree with the preorder traversal way, and return it.

Omit all the empty parenthesis pairs that do not affect the one-to-one mapping relationship between the string and the original binary tree.

**Example 1:**

![](https://assets.leetcode.com/uploads/2021/05/03/cons1-tree.jpg)

**Input:** root = [1,2,3,4]

**Output:** "1(2(4))(3)"

**Explanation:** Originally, it needs to be "1(2(4)())(3()())", but you need to omit all the unnecessary empty parenthesis pairs. And it will be "1(2(4))(3)"

**Example 2:**

![](https://assets.leetcode.com/uploads/2021/05/03/cons2-tree.jpg)

**Input:** root = [1,2,3,null,4]

**Output:** "1(2()(4))(3)"

**Explanation:** Almost the same as the first example, except we cannot omit the first parenthesis pair to break the one-to-one mapping relationship between the input and the output.

**Constraints:**

*   The number of nodes in the tree is in the range [1, 104].
*   `-1000 <= Node.val <= 1000`