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g1101_1200.s1177_can_make_palindrome_from_substring.readme.md Maven / Gradle / Ivy

1177\. Can Make Palindrome from Substring

Medium

You are given a string `s` and array `queries` where queries[i] = [lefti, righti, ki]. We may rearrange the substring s[lefti...righti] for each query and then choose up to ki of them to replace with any lowercase English letter.

If the substring is possible to be a palindrome string after the operations above, the result of the query is `true`. Otherwise, the result is `false`.

Return a boolean array `answer` where `answer[i]` is the result of the ith query `queries[i]`.

Note that each letter is counted individually for replacement, so if, for example s[lefti...righti] = "aaa", and ki = 2, we can only replace two of the letters. Also, note that no query modifies the initial string `s`.

**Example :**

**Input:** s = "abcda", queries = [[3,3,0],[1,2,0],[0,3,1],[0,3,2],[0,4,1]]

**Output:** [true,false,false,true,true]

**Explanation:** 

queries[0]: substring = "d", is palidrome. 

queries[1]: substring = "bc", is not palidrome. 

queries[2]: substring = "abcd", is not palidrome after replacing only 1 character. q

ueries[3]: substring = "abcd", could be changed to "abba" which is palidrome. Also this can be changed to "baab" first rearrange it "bacd" then replace "cd" with "ab". 

queries[4]: substring = "abcda", could be changed to "abcba" which is palidrome.

**Example 2:**

**Input:** s = "lyb", queries = [[0,1,0],[2,2,1]]

**Output:** [false,true]

**Constraints:**

*   1 <= s.length, queries.length <= 105
*   0 <= lefti <= righti < s.length
*   0 <= ki <= s.length
*   `s` consists of lowercase English letters.