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Java-based LeetCode algorithm problem solutions, regularly updated
package g0001_0100.s0065_valid_number;
// #Hard #String #2023_08_11_Time_1_ms_(100.00%)_Space_41.3_MB_(91.10%)
/**
* 65 - Valid Number\.
*
* Hard
*
* A **valid number** can be split up into these components (in order):
*
* 1. A **decimal number** or an **integer**.
* 2. (Optional) An `'e'` or `'E'`, followed by an **integer**.
*
* A **decimal number** can be split up into these components (in order):
*
* 1. (Optional) A sign character (either `'+'` or `'-'`).
* 2. One of the following formats:
* 1. One or more digits, followed by a dot `'.'`.
* 2. One or more digits, followed by a dot `'.'`, followed by one or more digits.
* 3. A dot `'.'`, followed by one or more digits.
*
* An **integer** can be split up into these components (in order):
*
* 1. (Optional) A sign character (either `'+'` or `'-'`).
* 2. One or more digits.
*
* For example, all the following are valid numbers: `["2", "0089", "-0.1", "+3.14", "4.", "-.9", "2e10", "-90E3", "3e+7", "+6e-1", "53.5e93", "-123.456e789"]`, while the following are not valid numbers: `["abc", "1a", "1e", "e3", "99e2.5", "--6", "-+3", "95a54e53"]`.
*
* Given a string `s`, return `true` _if_ `s` _is a **valid number**_.
*
* **Example 1:**
*
* **Input:** s = "0"
*
* **Output:** true
*
* **Example 2:**
*
* **Input:** s = "e"
*
* **Output:** false
*
* **Example 3:**
*
* **Input:** s = "."
*
* **Output:** false
*
* **Example 4:**
*
* **Input:** s = ".1"
*
* **Output:** true
*
* **Constraints:**
*
* * `1 <= s.length <= 20`
* * `s` consists of only English letters (both uppercase and lowercase), digits (`0-9`), plus `'+'`, minus `'-'`, or dot `'.'`.
**/
public class Solution {
public boolean isNumber(String s) {
if (s == null || s.length() == 0) {
return false;
}
boolean eSeen = false;
boolean numberSeen = false;
boolean decimalSeen = false;
for (int i = 0; i < s.length(); i++) {
char c = s.charAt(i);
if (c >= 48 && c <= 57) {
numberSeen = true;
} else if (c == '+' || c == '-') {
if (i == s.length() - 1
|| (i != 0 && s.charAt(i - 1) != 'e' && s.charAt(i - 1) != 'E')) {
return false;
}
} else if (c == '.') {
if (eSeen || decimalSeen) {
return false;
}
decimalSeen = true;
} else if (c == 'e' || c == 'E') {
if (i == s.length() - 1 || eSeen || !numberSeen) {
return false;
}
eSeen = true;
} else {
return false;
}
}
return numberSeen;
}
}
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