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Java-based LeetCode algorithm problem solutions, regularly updated
package g0101_0200.s0127_word_ladder;
// #Hard #Top_Interview_Questions #String #Hash_Table #Breadth_First_Search
// #Graph_Theory_I_Day_12_Breadth_First_Search
// #2022_06_23_Time_37_ms_(94.58%)_Space_54.1_MB_(66.08%)
import java.util.HashSet;
import java.util.List;
import java.util.Set;
/**
* 127 - Word Ladder\.
*
* Hard
*
* A **transformation sequence** from word `beginWord` to word `endWord` using a dictionary `wordList` is a sequence of words beginWord -> s1 -> s2 -> ... -> sk
such that:
*
* * Every adjacent pair of words differs by a single letter.
* * Every si
for `1 <= i <= k` is in `wordList`. Note that `beginWord` does not need to be in `wordList`.
* * sk == endWord
*
* Given two words, `beginWord` and `endWord`, and a dictionary `wordList`, return _the **number of words** in the **shortest transformation sequence** from_ `beginWord` _to_ `endWord`_, or_ `0` _if no such sequence exists._
*
* **Example 1:**
*
* **Input:** beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log","cog"]
*
* **Output:** 5
*
* **Explanation:** One shortest transformation sequence is "hit" -> "hot" -> "dot" -> "dog" -> cog", which is 5 words long.
*
* **Example 2:**
*
* **Input:** beginWord = "hit", endWord = "cog", wordList = ["hot","dot","dog","lot","log"]
*
* **Output:** 0
*
* **Explanation:** The endWord "cog" is not in wordList, therefore there is no valid transformation sequence.
*
* **Constraints:**
*
* * `1 <= beginWord.length <= 10`
* * `endWord.length == beginWord.length`
* * `1 <= wordList.length <= 5000`
* * `wordList[i].length == beginWord.length`
* * `beginWord`, `endWord`, and `wordList[i]` consist of lowercase English letters.
* * `beginWord != endWord`
* * All the words in `wordList` are **unique**.
**/
public class Solution {
public int ladderLength(String beginWord, String endWord, List wordDict) {
Set beginSet = new HashSet<>();
Set endSet = new HashSet<>();
Set wordSet = new HashSet<>(wordDict);
Set visited = new HashSet<>();
if (!wordDict.contains(endWord)) {
return 0;
}
int len = 1;
int strLen = beginWord.length();
beginSet.add(beginWord);
endSet.add(endWord);
while (!beginSet.isEmpty() && !endSet.isEmpty()) {
if (beginSet.size() > endSet.size()) {
Set temp = beginSet;
beginSet = endSet;
endSet = temp;
}
Set tempSet = new HashSet<>();
for (String s : beginSet) {
char[] chars = s.toCharArray();
for (int i = 0; i < strLen; i++) {
char old = chars[i];
for (char j = 'a'; j <= 'z'; j++) {
chars[i] = j;
String temp = new String(chars);
if (endSet.contains(temp)) {
return len + 1;
}
if (!visited.contains(temp) && wordSet.contains(temp)) {
tempSet.add(temp);
visited.add(temp);
}
}
chars[i] = old;
}
}
beginSet = tempSet;
len++;
}
return 0;
}
}
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