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Java-based LeetCode algorithm problem solutions, regularly updated
package g0101_0200.s0136_single_number;
// #Easy #Top_100_Liked_Questions #Top_Interview_Questions #Array #Bit_Manipulation
// #Data_Structure_II_Day_1_Array #Algorithm_I_Day_14_Bit_Manipulation #Udemy_Integers
// #Big_O_Time_O(N)_Space_O(1) #2022_06_24_Time_1_ms_(99.97%)_Space_50.9_MB_(35.58%)
/**
* 136 - Single Number\.
*
* Easy
*
* Given a **non-empty** array of integers `nums`, every element appears _twice_ except for one. Find that single one.
*
* You must implement a solution with a linear runtime complexity and use only constant extra space.
*
* **Example 1:**
*
* **Input:** nums = [2,2,1]
*
* **Output:** 1
*
* **Example 2:**
*
* **Input:** nums = [4,1,2,1,2]
*
* **Output:** 4
*
* **Example 3:**
*
* **Input:** nums = [1]
*
* **Output:** 1
*
* **Constraints:**
*
* * 1 <= nums.length <= 3 * 104
* * -3 * 104 <= nums[i] <= 3 * 104
* * Each element in the array appears twice except for one element which appears only once.
**/
public class Solution {
public int singleNumber(int[] nums) {
int res = 0;
for (int num : nums) {
res ^= num;
}
return res;
}
}
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