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Java-based LeetCode algorithm problem solutions, regularly updated
package g0201_0300.s0241_different_ways_to_add_parentheses;
// #Medium #String #Dynamic_Programming #Math #Recursion #Memoization
// #2022_07_05_Time_3_ms_(70.81%)_Space_42.5_MB_(73.65%)
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
/**
* 241 - Different Ways to Add Parentheses\.
*
* Medium
*
* Given a string `expression` of numbers and operators, return _all possible results from computing all the different possible ways to group numbers and operators_. You may return the answer in **any order**.
*
* **Example 1:**
*
* **Input:** expression = "2-1-1"
*
* **Output:** [0,2]
*
* **Explanation:** ((2-1)-1) = 0 (2-(1-1)) = 2
*
* **Example 2:**
*
* **Input:** expression = "2\*3-4\*5"
*
* **Output:** [-34,-14,-10,-10,10]
*
* **Explanation:**
*
* (2*(3-(4*5))) = -34
* ((2*3)-(4*5)) = -14
* ((2*(3-4))*5) = -10
* (2*((3-4)*5)) = -10
* (((2*3)-4)*5) = 10
*
* **Constraints:**
*
* * `1 <= expression.length <= 20`
* * `expression` consists of digits and the operator `'+'`, `'-'`, and `'*'`.
* * All the integer values in the input expression are in the range `[0, 99]`.
**/
public class Solution {
public List diffWaysToCompute(String expression) {
return diffWaysToCompute(expression, new HashMap<>());
}
private List diffWaysToCompute(String expression, Map> map) {
if (map.containsKey(expression)) {
return map.get(expression);
}
List values = new ArrayList<>();
if (!hasOperator(expression)) {
// base case
values.add(Integer.parseInt(expression));
} else {
// Recursive case. DFS
for (int i = 0; i < expression.length(); i++) {
char symbol = expression.charAt(i);
if (!Character.isDigit(symbol)) {
List left = diffWaysToCompute(expression.substring(0, i), map);
List right = diffWaysToCompute(expression.substring(i + 1), map);
for (Integer l : left) {
for (Integer r : right) {
switch (symbol) {
case '+':
values.add(l + r);
break;
case '-':
values.add(l - r);
break;
case '*':
values.add(l * r);
break;
default:
break;
}
}
}
}
}
}
map.put(expression, values);
return values;
}
private boolean hasOperator(String expression) {
for (int i = 0; i < expression.length(); i++) {
switch (expression.charAt(i)) {
case '+':
case '-':
case '*':
return true;
default:
break;
}
}
return false;
}
}
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