g0301_0400.s0383_ransom_note.Solution Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g0301_0400.s0383_ransom_note;
// #Easy #String #Hash_Table #Counting #Data_Structure_I_Day_6_String
// #2022_07_13_Time_1_ms_(99.97%)_Space_46_MB_(62.86%)
/**
* 383 - Ransom Note\.
*
* Easy
*
* Given two stings `ransomNote` and `magazine`, return `true` if `ransomNote` can be constructed from `magazine` and `false` otherwise.
*
* Each letter in `magazine` can only be used once in `ransomNote`.
*
* **Example 1:**
*
* **Input:** ransomNote = "a", magazine = "b"
*
* **Output:** false
*
* **Example 2:**
*
* **Input:** ransomNote = "aa", magazine = "ab"
*
* **Output:** false
*
* **Example 3:**
*
* **Input:** ransomNote = "aa", magazine = "aab"
*
* **Output:** true
*
* **Constraints:**
*
* * 1 <= ransomNote.length, magazine.length <= 105
* * `ransomNote` and `magazine` consist of lowercase English letters.
**/
public class Solution {
public boolean canConstruct(String ransomNote, String magazine) {
int[] a = new int[26];
int n = ransomNote.length();
for (int i = 0; i < n; i++) {
a[ransomNote.charAt(i) - 97]++;
}
for (int i = 0; i < magazine.length() && n != 0; i++) {
if (a[magazine.charAt(i) - 97] > 0) {
n--;
a[magazine.charAt(i) - 97]--;
}
}
return n == 0;
}
}
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