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Java-based LeetCode algorithm problem solutions, regularly updated
package g0601_0700.s0662_maximum_width_of_binary_tree;
// #Medium #Depth_First_Search #Breadth_First_Search #Tree #Binary_Tree
// #2022_03_21_Time_2_ms_(78.93%)_Space_43.8_MB_(35.13%)
import com_github_leetcode.TreeNode;
import java.util.LinkedList;
import java.util.Objects;
import java.util.Queue;
/*
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
/**
* 662 - Maximum Width of Binary Tree\.
*
* Medium
*
* Given the `root` of a binary tree, return _the **maximum width** of the given tree_.
*
* The **maximum width** of a tree is the maximum **width** among all levels.
*
* The **width** of one level is defined as the length between the end-nodes (the leftmost and rightmost non-null nodes), where the null nodes between the end-nodes are also counted into the length calculation.
*
* It is **guaranteed** that the answer will in the range of **32-bit** signed integer.
*
* **Example 1:**
*
* ![](https://assets.leetcode.com/uploads/2021/05/03/width1-tree.jpg)
*
* **Input:** root = [1,3,2,5,3,null,9]
*
* **Output:** 4
*
* **Explanation:** The maximum width existing in the third level with the length 4 (5,3,null,9).
*
* **Example 2:**
*
* ![](https://assets.leetcode.com/uploads/2021/05/03/width2-tree.jpg)
*
* **Input:** root = [1,3,null,5,3]
*
* **Output:** 2
*
* **Explanation:** The maximum width existing in the third level with the length 2 (5,3).
*
* **Example 3:**
*
* ![](https://assets.leetcode.com/uploads/2021/05/03/width3-tree.jpg)
*
* **Input:** root = [1,3,2,5]
*
* **Output:** 2
*
* **Explanation:** The maximum width existing in the second level with the length 2 (3,2).
*
* **Constraints:**
*
* * The number of nodes in the tree is in the range `[1, 3000]`.
* * `-100 <= Node.val <= 100`
**/
public class Solution {
static class Pair {
TreeNode node;
int idx;
public Pair(TreeNode node, int idx) {
this.node = node;
this.idx = idx;
}
}
public int widthOfBinaryTree(TreeNode root) {
Queue q = new LinkedList<>();
q.add(new Pair(root, 0));
int res = 1;
while (!q.isEmpty()) {
int qSize = q.size();
int lastIdx = 0;
int firstIdx = 0;
for (int i = 0; i < qSize; i++) {
Pair temp = q.poll();
if (i == 0) {
firstIdx = temp.idx;
}
if (i == qSize - 1) {
lastIdx = Objects.requireNonNull(temp).idx;
}
if (Objects.requireNonNull(temp).node.left != null) {
q.add(new Pair(temp.node.left, 2 * (temp.idx) + 1));
}
if (temp.node.right != null) {
q.add(new Pair(temp.node.right, 2 * (temp.idx) + 2));
}
}
res = Math.max((lastIdx - firstIdx) + 1, res);
}
return res;
}
}
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