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Java-based LeetCode algorithm problem solutions, regularly updated
package g0801_0900.s0818_race_car;
// #Hard #Dynamic_Programming #2022_03_23_Time_9_ms_(82.90%)_Space_44.2_MB_(70.46%)
import java.util.LinkedList;
import java.util.Queue;
/**
* 818 - Race Car\.
*
* Hard
*
* Your car starts at position `0` and speed `+1` on an infinite number line. Your car can go into negative positions. Your car drives automatically according to a sequence of instructions `'A'` (accelerate) and `'R'` (reverse):
*
* * When you get an instruction `'A'`, your car does the following:
* * `position += speed`
* * `speed *= 2`
* * When you get an instruction `'R'`, your car does the following:
* * If your speed is positive then `speed = -1`
* * otherwise `speed = 1`Your position stays the same.
*
* For example, after commands `"AAR"`, your car goes to positions `0 --> 1 --> 3 --> 3`, and your speed goes to `1 --> 2 --> 4 --> -1`.
*
* Given a target position `target`, return _the length of the shortest sequence of instructions to get there_.
*
* **Example 1:**
*
* **Input:** target = 3
*
* **Output:** 2
*
* **Explanation:**
*
* The shortest instruction sequence is "AA".
*
* Your position goes from 0 --> 1 --> 3.
*
* **Example 2:**
*
* **Input:** target = 6
*
* **Output:** 5
*
* **Explanation:**
*
* The shortest instruction sequence is "AAARA".
*
* Your position goes from 0 --> 1 --> 3 --> 7 --> 7 --> 6.
*
* **Constraints:**
*
* * 1 <= target <= 104
**/
public class Solution {
public int racecar(int target) {
Queue queue = new LinkedList<>();
queue.add(new int[] {0, 1, 0});
while (!queue.isEmpty()) {
int[] arr = queue.poll();
if (arr[0] == target) {
return arr[2];
}
queue.add(new int[] {arr[0] + arr[1], 2 * arr[1], 1 + arr[2]});
if ((arr[0] + arr[1]) > target && arr[1] > 0) {
queue.add(new int[] {arr[0], -1, 1 + arr[2]});
}
if ((arr[0]) + arr[1] < target && (arr[1] < 0)) {
queue.add(new int[] {arr[0], 1, 1 + arr[2]});
}
}
return -1;
}
}
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