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Java-based LeetCode algorithm problem solutions, regularly updated
package g0801_0900.s0846_hand_of_straights;
// #Medium #Array #Hash_Table #Sorting #Greedy #2022_03_24_Time_19_ms_(96.16%)_Space_43_MB_(93.42%)
import java.util.Arrays;
import java.util.HashMap;
import java.util.Map;
/**
* 846 - Hand of Straights\.
*
* Medium
*
* Alice has some number of cards and she wants to rearrange the cards into groups so that each group is of size `groupSize`, and consists of `groupSize` consecutive cards.
*
* Given an integer array `hand` where `hand[i]` is the value written on the ith
card and an integer `groupSize`, return `true` if she can rearrange the cards, or `false` otherwise.
*
* **Example 1:**
*
* **Input:** hand = [1,2,3,6,2,3,4,7,8], groupSize = 3
*
* **Output:** true
*
* **Explanation:** Alice's hand can be rearranged as [1,2,3],[2,3,4],[6,7,8]
*
* **Example 2:**
*
* **Input:** hand = [1,2,3,4,5], groupSize = 4
*
* **Output:** false
*
* **Explanation:** Alice's hand can not be rearranged into groups of 4.
*
* **Constraints:**
*
* * 1 <= hand.length <= 104
* * 0 <= hand[i] <= 109
* * `1 <= groupSize <= hand.length`
*
* **Note:** This question is the same as 1296: [https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/](https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/)
**/
public class Solution {
public boolean isNStraightHand(int[] hand, int groupSize) {
int len = hand.length;
if (len % groupSize != 0) {
return false;
}
Arrays.sort(hand);
Map map = new HashMap<>();
for (int num : hand) {
int cnt = map.getOrDefault(num, 0);
map.put(num, ++cnt);
}
for (int num : hand) {
int cnt = map.get(num);
if (cnt <= 0) {
continue;
}
map.put(num, --cnt);
int loop = 1;
while (loop < groupSize) {
int curCnt = map.getOrDefault(num + loop, 0);
if (curCnt <= 0) {
return false;
}
map.put(num + loop, --curCnt);
++loop;
}
}
return true;
}
}
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