g0901_1000.s0925_long_pressed_name.Solution Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-java21 Show documentation
Show all versions of leetcode-in-java21 Show documentation
Java-based LeetCode algorithm problem solutions, regularly updated
package g0901_1000.s0925_long_pressed_name;
// #Easy #String #Two_Pointers #2022_03_29_Time_1_ms_(84.87%)_Space_40.1_MB_(93.12%)
/**
* 925 - Long Pressed Name\.
*
* Easy
*
* Your friend is typing his `name` into a keyboard. Sometimes, when typing a character `c`, the key might get _long pressed_, and the character will be typed 1 or more times.
*
* You examine the `typed` characters of the keyboard. Return `True` if it is possible that it was your friends name, with some characters (possibly none) being long pressed.
*
* **Example 1:**
*
* **Input:** name = "alex", typed = "aaleex"
*
* **Output:** true
*
* **Explanation:** 'a' and 'e' in 'alex' were long pressed.
*
* **Example 2:**
*
* **Input:** name = "saeed", typed = "ssaaedd"
*
* **Output:** false
*
* **Explanation:** 'e' must have been pressed twice, but it was not in the typed output.
*
* **Constraints:**
*
* * `1 <= name.length, typed.length <= 1000`
* * `name` and `typed` consist of only lowercase English letters.
**/
public class Solution {
public boolean isLongPressedName(String name, String typed) {
int i = 0;
int j = 0;
char prev = '$';
if (typed.length() < name.length()) {
return false;
}
while (i < name.length() && j < typed.length()) {
while (j < typed.length() && typed.charAt(j) != name.charAt(i)) {
if (typed.charAt(j) != prev) {
return false;
}
if (j == typed.length() - 1) {
return false;
}
j++;
}
prev = name.charAt(i);
i++;
j++;
}
if (i < name.length()) {
return false;
}
for (; j < typed.length(); j++) {
if (typed.charAt(j) != prev) {
return false;
}
}
return true;
}
}
© 2015 - 2025 Weber Informatics LLC | Privacy Policy