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Java-based LeetCode algorithm problem solutions, regularly updated
package g0901_1000.s0972_equal_rational_numbers;
// #Hard #String #Math #2022_03_31_Time_4_ms_(56.67%)_Space_43.5_MB_(6.67%)
/**
* 972 - Equal Rational Numbers\.
*
* Hard
*
* Given two strings `s` and `t`, each of which represents a non-negative rational number, return `true` if and only if they represent the same number. The strings may use parentheses to denote the repeating part of the rational number.
*
* A **rational number** can be represented using up to three parts: `<IntegerPart>`, `<NonRepeatingPart>`, and a `<RepeatingPart>`. The number will be represented in one of the following three ways:
*
* * `<IntegerPart>`
* * For example, `12`, `0`, and `123`.
* * `<IntegerPart>**<.>**<NonRepeatingPart>`
* * For example, `0.5`, `1.`, `2.12`, and `123.0001`.
* * `<IntegerPart>**<.>**<NonRepeatingPart>**<(>**<RepeatingPart>**<)>**`
* * For example, `0.1(6)`, `1.(9)`, `123.00(1212)`.
*
* The repeating portion of a decimal expansion is conventionally denoted within a pair of round brackets. For example:
*
* * `1/6 = 0.16666666... = 0.1(6) = 0.1666(6) = 0.166(66)`.
*
* **Example 1:**
*
* **Input:** s = "0.(52)", t = "0.5(25)"
*
* **Output:** true
*
* **Explanation:** Because "0.(52)" represents 0.52525252..., and "0.5(25)" represents 0.52525252525..... , the strings represent the same number.
*
* **Example 2:**
*
* **Input:** s = "0.1666(6)", t = "0.166(66)"
*
* **Output:** true
*
* **Example 3:**
*
* **Input:** s = "0.9(9)", t = "1."
*
* **Output:** true
*
* **Explanation:** "0.9(9)" represents 0.999999999... repeated forever, which equals
*
* 1. [[See this link for an explanation.](https://en.wikipedia.org/wiki/0.999...)] "1." represents the number 1, which is formed correctly: (IntegerPart) = "1" and (NonRepeatingPart) = "".
*
* **Constraints:**
*
* * Each part consists only of digits.
* * The `<IntegerPart>` does not have leading zeros (except for the zero itself).
* * `1 <= <IntegerPart>.length <= 4`
* * `0 <= <NonRepeatingPart>.length <= 4`
* * `1 <= <RepeatingPart>.length <= 4`
**/
public class Solution {
public boolean isRationalEqual(String s, String t) {
int sLeftIndex = s.indexOf("(");
int tLeftIndex = t.indexOf("(");
// if they are integer or only with non repeating part
if (sLeftIndex < 0 && tLeftIndex < 0) {
return Double.valueOf(s).equals(Double.valueOf(t));
}
// get the first 100 (or so) digits of s and t
double sDouble;
double tDouble;
if (sLeftIndex >= 0) {
s = s.substring(0, sLeftIndex) + repeat(s.substring(sLeftIndex + 1, s.length() - 1));
sDouble = Double.parseDouble(s.substring(0, 100));
} else {
sDouble = Double.parseDouble(s);
}
if (tLeftIndex >= 0) {
t = t.substring(0, tLeftIndex) + repeat(t.substring(tLeftIndex + 1, t.length() - 1));
tDouble = Double.parseDouble(t.substring(0, 100));
} else {
tDouble = Double.parseDouble(t);
}
return sDouble == tDouble;
}
private String repeat(String a) {
StringBuilder sb = new StringBuilder();
for (int i = 0; i < 100; i++) {
sb.append(a);
}
return sb.toString();
}
}
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