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Java-based LeetCode algorithm problem solutions, regularly updated
package g0901_1000.s0991_broken_calculator;
// #Medium #Math #Greedy #2022_03_31_Time_0_ms_(100.00%)_Space_41.1_MB_(40.35%)
/**
* 991 - Broken Calculator\.
*
* Medium
*
* There is a broken calculator that has the integer `startValue` on its display initially. In one operation, you can:
*
* * multiply the number on display by `2`, or
* * subtract `1` from the number on display.
*
* Given two integers `startValue` and `target`, return _the minimum number of operations needed to display_ `target` _on the calculator_.
*
* **Example 1:**
*
* **Input:** startValue = 2, target = 3
*
* **Output:** 2
*
* **Explanation:** Use double operation and then decrement operation {2 -> 4 -> 3}.
*
* **Example 2:**
*
* **Input:** startValue = 5, target = 8
*
* **Output:** 2
*
* **Explanation:** Use decrement and then double {5 -> 4 -> 8}.
*
* **Example 3:**
*
* **Input:** startValue = 3, target = 10
*
* **Output:** 3
*
* **Explanation:** Use double, decrement and double {3 -> 6 -> 5 -> 10}.
*
* **Constraints:**
*
* * 1 <= x, y <= 109
**/
public class Solution {
public int brokenCalc(int startValue, int target) {
int result = 0;
while (startValue != target) {
if (target > startValue && target % 2 != 0) {
target += 1;
result++;
} else if (target > startValue) {
target /= 2;
result++;
} else {
result += startValue - target;
break;
}
}
return result;
}
}
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