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Java-based LeetCode algorithm problem solutions, regularly updated
package g1001_1100.s1032_stream_of_characters;
// #Hard #Array #String #Design #Trie #Data_Stream
// #2022_02_27_Time_137_ms_(81.54%)_Space_148.2_MB_(53.37%)
/**
* 1032 - Stream of Characters\.
*
* Hard
*
* Design an algorithm that accepts a stream of characters and checks if a suffix of these characters is a string of a given array of strings `words`.
*
* For example, if `words = ["abc", "xyz"]` and the stream added the four characters (one by one) `'a'`, `'x'`, `'y'`, and `'z'`, your algorithm should detect that the suffix `"xyz"` of the characters `"axyz"` matches `"xyz"` from `words`.
*
* Implement the `StreamChecker` class:
*
* * `StreamChecker(String[] words)` Initializes the object with the strings array `words`.
* * `boolean query(char letter)` Accepts a new character from the stream and returns `true` if any non-empty suffix from the stream forms a word that is in `words`.
*
* **Example 1:**
*
* **Input** ["StreamChecker", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query", "query"] [[["cd", "f", "kl"]], ["a"], ["b"], ["c"], ["d"], ["e"], ["f"], ["g"], ["h"], ["i"], ["j"], ["k"], ["l"]]
*
* **Output:** [null, false, false, false, true, false, true, false, false, false, false, false, true]
*
* **Explanation:**
*
* StreamChecker streamChecker = new StreamChecker(["cd", "f", "kl"]);
* streamChecker.query("a"); // return False
* streamChecker.query("b"); // return False
* streamChecker.query("c"); // return False
* streamChecker.query("d"); // return True, because 'cd' is in the wordlist
* streamChecker.query("e"); // return False
* streamChecker.query("f"); // return True, because 'f' is in the wordlist
* streamChecker.query("g"); // return False
* streamChecker.query("h"); // return False
* streamChecker.query("i"); // return False
* streamChecker.query("j"); // return False
* streamChecker.query("k"); // return False
* streamChecker.query("l"); // return True, because 'kl' is in the wordlist
*
* **Constraints:**
*
* * `1 <= words.length <= 2000`
* * `1 <= words[i].length <= 2000`
* * `words[i]` consists of lowercase English letters.
* * `letter` is a lowercase English letter.
* * At most 4 * 104
calls will be made to query.
**/
public class StreamChecker {
static class Node {
Node[] child;
boolean isEnd;
Node() {
child = new Node[26];
}
}
private final StringBuilder sb;
private final Node root;
public void insert(String s) {
Node curr = root;
for (int i = s.length() - 1; i >= 0; i--) {
char c = s.charAt(i);
if (curr.child[c - 'a'] == null) {
curr.child[c - 'a'] = new Node();
}
curr = curr.child[c - 'a'];
}
curr.isEnd = true;
}
public StreamChecker(String[] words) {
root = new Node();
sb = new StringBuilder();
for (String s : words) {
insert(s);
}
}
public boolean query(char letter) {
sb.append(letter);
Node curr = root;
for (int i = sb.length() - 1; i >= 0; i--) {
char c = sb.charAt(i);
if (curr.child[c - 'a'] == null) {
return false;
}
if (curr.child[c - 'a'].isEnd) {
return true;
}
curr = curr.child[c - 'a'];
}
return false;
}
}
/*
* Your StreamChecker object will be instantiated and called as such:
* StreamChecker obj = new StreamChecker(words);
* boolean param_1 = obj.query(letter);
*/
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