g1001_1100.s1073_adding_two_negabinary_numbers.Solution Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1001_1100.s1073_adding_two_negabinary_numbers;
// #Medium #Array #Math #2022_02_27_Time_1_ms_(100.00%)_Space_42.4_MB_(57.83%)
/**
* 1073 - Adding Two Negabinary Numbers\.
*
* Medium
*
* Given two numbers `arr1` and `arr2` in base **\-2** , return the result of adding them together.
*
* Each number is given in _array format_: as an array of 0s and 1s, from most significant bit to least significant bit. For example, `arr = [1,1,0,1]` represents the number `(-2)^3 + (-2)^2 + (-2)^0 = -3`. A number `arr` in _array, format_ is also guaranteed to have no leading zeros: either `arr == [0]` or `arr[0] == 1`.
*
* Return the result of adding `arr1` and `arr2` in the same format: as an array of 0s and 1s with no leading zeros.
*
* **Example 1:**
*
* **Input:** arr1 = [1,1,1,1,1], arr2 = [1,0,1]
*
* **Output:** [1,0,0,0,0]
*
* **Explanation:** arr1 represents 11, arr2 represents 5, the output represents 16.
*
* **Example 2:**
*
* **Input:** arr1 = [0], arr2 = [0]
*
* **Output:** [0]
*
* **Example 3:**
*
* **Input:** arr1 = [0], arr2 = [1]
*
* **Output:** [1]
*
* **Constraints:**
*
* * `1 <= arr1.length, arr2.length <= 1000`
* * `arr1[i]` and `arr2[i]` are `0` or `1`
* * `arr1` and `arr2` have no leading zeros
**/
public class Solution {
public int[] addNegabinary(int[] arr1, int[] arr2) {
int len1 = arr1.length;
int len2 = arr2.length;
int[] reverseArr1 = new int[len1];
for (int i = len1 - 1; i >= 0; i--) {
reverseArr1[len1 - i - 1] = arr1[i];
}
int[] reverseArr2 = new int[len2];
for (int i = len2 - 1; i >= 0; i--) {
reverseArr2[len2 - i - 1] = arr2[i];
}
int[] sumArray = new int[Math.max(len1, len2) + 2];
System.arraycopy(reverseArr1, 0, sumArray, 0, len1);
for (int i = 0; i < sumArray.length; i++) {
if (i < len2) {
sumArray[i] += reverseArr2[i];
}
if (sumArray[i] > 1) {
sumArray[i] -= 2;
sumArray[i + 1]--;
} else if (sumArray[i] == -1) {
sumArray[i] = 1;
sumArray[i + 1]++;
}
}
int resultLen = sumArray.length;
for (int i = sumArray.length - 1; i >= 0; i--) {
if (sumArray[i] == 0) {
resultLen--;
} else {
break;
}
}
if (resultLen == 0) {
return new int[] {0};
}
int[] result = new int[resultLen];
for (int i = resultLen - 1; i >= 0; i--) {
result[resultLen - i - 1] = sumArray[i];
}
return result;
}
}
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