g1101_1200.s1116_print_zero_even_odd.ZeroEvenOdd Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1101_1200.s1116_print_zero_even_odd;
// #Medium #Concurrency #2023_06_01_Time_7_ms_(38.76%)_Space_42_MB_(38.97%)
import java.util.concurrent.Semaphore;
import java.util.function.IntConsumer;
/**
* 1116 - Print Zero Even Odd\.
*
* Medium
*
* You have a function `printNumber` that can be called with an integer parameter and prints it to the console.
*
* * For example, calling `printNumber(7)` prints `7` to the console.
*
* You are given an instance of the class `ZeroEvenOdd` that has three functions: `zero`, `even`, and `odd`. The same instance of `ZeroEvenOdd` will be passed to three different threads:
*
* * **Thread A:** calls `zero()` that should only output `0`'s.
* * **Thread B:** calls `even()` that should only output even numbers.
* * **Thread C:** calls `odd()` that should only output odd numbers.
*
* Modify the given class to output the series `"010203040506..."` where the length of the series must be `2n`.
*
* Implement the `ZeroEvenOdd` class:
*
* * `ZeroEvenOdd(int n)` Initializes the object with the number `n` that represents the numbers that should be printed.
* * `void zero(printNumber)` Calls `printNumber` to output one zero.
* * `void even(printNumber)` Calls `printNumber` to output one even number.
* * `void odd(printNumber)` Calls `printNumber` to output one odd number.
*
* **Example 1:**
*
* **Input:** n = 2
*
* **Output:** "0102"
*
* **Explanation:** There are three threads being fired asynchronously. One of them calls zero(), the other calls even(), and the last one calls odd(). "0102" is the correct output.
*
* **Example 2:**
*
* **Input:** n = 5
*
* **Output:** "0102030405"
*
* **Constraints:**
*
* * `1 <= n <= 1000`
**/
@SuppressWarnings({"java:S2142", "java:S2583"})
public class ZeroEvenOdd {
private int n;
private final Semaphore zeroSemaphore = new Semaphore(1);
private final Semaphore oddSemaphore = new Semaphore(1);
private final Semaphore evenSemaphore = new Semaphore(1);
public ZeroEvenOdd(int n) {
this.n = n;
try {
oddSemaphore.acquire();
evenSemaphore.acquire();
} catch (InterruptedException ignored) {
// ignored
}
}
// printNumber.accept(x) outputs "x", where x is an integer.
public void zero(IntConsumer printNumber) throws InterruptedException {
for (int i = 1; i <= n; i++) {
zeroSemaphore.acquire();
printNumber.accept(0);
if (i % 2 == 0) {
oddSemaphore.release();
} else {
evenSemaphore.release();
}
}
oddSemaphore.release();
evenSemaphore.release();
}
public void odd(IntConsumer printNumber) throws InterruptedException {
for (int i = 1; i <= n; i += 2) {
evenSemaphore.acquire();
if (i > n) {
zeroSemaphore.release();
evenSemaphore.release();
break;
}
printNumber.accept(i);
zeroSemaphore.release();
}
}
public void even(IntConsumer printNumber) throws InterruptedException {
for (int i = 2; i <= n; i += 2) {
oddSemaphore.acquire();
if (i > n) {
zeroSemaphore.release();
oddSemaphore.release();
break;
}
printNumber.accept(i);
zeroSemaphore.release();
}
}
}
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