g1101_1200.s1184_distance_between_bus_stops.Solution Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1101_1200.s1184_distance_between_bus_stops;
// #Easy #Array #2022_03_03_Time_0_ms_(100.00%)_Space_43.9_MB_(5.55%)
/**
* 1184 - Distance Between Bus Stops\.
*
* Easy
*
* A bus has `n` stops numbered from `0` to `n - 1` that form a circle. We know the distance between all pairs of neighboring stops where `distance[i]` is the distance between the stops number `i` and `(i + 1) % n`.
*
* The bus goes along both directions i.e. clockwise and counterclockwise.
*
* Return the shortest distance between the given `start` and `destination` stops.
*
* **Example 1:**
*
* ![](https://assets.leetcode.com/uploads/2019/09/03/untitled-diagram-1.jpg)
*
* **Input:** distance = [1,2,3,4], start = 0, destination = 1
*
* **Output:** 1
*
* **Explanation:** Distance between 0 and 1 is 1 or 9, minimum is 1.
*
* **Example 2:**
*
* ![](https://assets.leetcode.com/uploads/2019/09/03/untitled-diagram-1-1.jpg)
*
* **Input:** distance = [1,2,3,4], start = 0, destination = 2
*
* **Output:** 3
*
* **Explanation:** Distance between 0 and 2 is 3 or 7, minimum is 3.
*
* **Example 3:**
*
* ![](https://assets.leetcode.com/uploads/2019/09/03/untitled-diagram-1-2.jpg)
*
* **Input:** distance = [1,2,3,4], start = 0, destination = 3
*
* **Output:** 4
*
* **Explanation:** Distance between 0 and 3 is 6 or 4, minimum is 4.
*
* **Constraints:**
*
* * `1 <= n <= 10^4`
* * `distance.length == n`
* * `0 <= start, destination < n`
* * `0 <= distance[i] <= 10^4`
**/
public class Solution {
public int distanceBetweenBusStops(int[] distance, int start, int destination) {
if (start > destination) {
int tmp = start;
start = destination;
destination = tmp;
}
int clockwise = 0;
for (int i = start; i < destination; i++) {
clockwise += distance[i];
}
int counterClockwise = 0;
for (int i = destination; i < distance.length; i++) {
counterClockwise += distance[i];
}
for (int i = 0; i < start; i++) {
counterClockwise += distance[i];
}
return Math.min(clockwise, counterClockwise);
}
}
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