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Java-based LeetCode algorithm problem solutions, regularly updated
package g1401_1500.s1462_course_schedule_iv;
// #Medium #Depth_First_Search #Breadth_First_Search #Graph #Topological_Sort
// #2022_03_29_Time_10_ms_(100.00%)_Space_46.3_MB_(94.57%)
import java.util.ArrayList;
import java.util.HashMap;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.Queue;
/**
* 1462 - Course Schedule IV\.
*
* Medium
*
* There are a total of `numCourses` courses you have to take, labeled from `0` to `numCourses - 1`. You are given an array `prerequisites` where prerequisites[i] = [ai, bi]
indicates that you **must** take course ai
first if you want to take course bi
.
*
* * For example, the pair `[0, 1]` indicates that you have to take course `0` before you can take course `1`.
*
* Prerequisites can also be **indirect**. If course `a` is a prerequisite of course `b`, and course `b` is a prerequisite of course `c`, then course `a` is a prerequisite of course `c`.
*
* You are also given an array `queries` where queries[j] = [uj, vj]
. For the jth
query, you should answer whether course uj
is a prerequisite of course vj
or not.
*
* Return _a boolean array_ `answer`_, where_ `answer[j]` _is the answer to the_ jth
_query._
*
* **Example 1:**
*
* ![](https://assets.leetcode.com/uploads/2021/05/01/courses4-1-graph.jpg)
*
* **Input:** numCourses = 2, prerequisites = \[\[1,0]], queries = \[\[0,1],[1,0]]
*
* **Output:** [false,true]
*
* **Explanation:** The pair [1, 0] indicates that you have to take course 1 before you can take course 0. Course 0 is not a prerequisite of course 1, but the opposite is true.
*
* **Example 2:**
*
* **Input:** numCourses = 2, prerequisites = [], queries = \[\[1,0],[0,1]]
*
* **Output:** [false,false]
*
* **Explanation:** There are no prerequisites, and each course is independent.
*
* **Example 3:**
*
* ![](https://assets.leetcode.com/uploads/2021/05/01/courses4-3-graph.jpg)
*
* **Input:** numCourses = 3, prerequisites = \[\[1,2],[1,0],[2,0]], queries = \[\[1,0],[1,2]]
*
* **Output:** [true,true]
*
* **Constraints:**
*
* * `2 <= numCourses <= 100`
* * `0 <= prerequisites.length <= (numCourses * (numCourses - 1) / 2)`
* * `prerequisites[i].length == 2`
* * 0 <= ai, bi <= n - 1
* * ai != bi
* * All the pairs [ai, bi]
are **unique**.
* * The prerequisites graph has no cycles.
* * 1 <= queries.length <= 104
* * 0 <= ui, vi <= n - 1
* * ui != vi
**/
public class Solution {
public List checkIfPrerequisite(
int numCourses, int[][] prerequisites, int[][] queries) {
Map> m = new HashMap<>();
int[] ind = new int[numCourses];
for (int[] p : prerequisites) {
m.computeIfAbsent(p[1], o -> new ArrayList<>()).add(p[0]);
ind[p[0]]++;
}
boolean[][] r = new boolean[numCourses][numCourses];
Queue q = new LinkedList<>();
for (int i = 0; i < numCourses; i++) {
if (ind[i] == 0) {
q.add(i);
}
}
while (!q.isEmpty()) {
int j = q.poll();
for (int k : m.getOrDefault(j, new ArrayList<>())) {
r[k][j] = true;
for (int l = 0; l < r.length; l++) {
if (r[j][l]) {
r[k][l] = true;
}
}
ind[k]--;
if (ind[k] == 0) {
q.offer(k);
}
}
}
List a = new ArrayList<>();
for (int[] qr : queries) {
a.add(r[qr[0]][qr[1]]);
}
return a;
}
}
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