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Java-based LeetCode algorithm problem solutions, regularly updated
package g1601_1700.s1609_even_odd_tree;
// #Medium #Breadth_First_Search #Tree #Binary_Tree
// #2022_04_12_Time_8_ms_(98.81%)_Space_56.9_MB_(99.32%)
import com_github_leetcode.TreeNode;
import java.util.ArrayList;
import java.util.List;
/**
* 1609 - Even Odd Tree\.
*
* Medium
*
* A binary tree is named **Even-Odd** if it meets the following conditions:
*
* * The root of the binary tree is at level index `0`, its children are at level index `1`, their children are at level index `2`, etc.
* * For every **even-indexed** level, all nodes at the level have **odd** integer values in **strictly increasing** order (from left to right).
* * For every **odd-indexed** level, all nodes at the level have **even** integer values in **strictly decreasing** order (from left to right).
*
* Given the `root` of a binary tree, _return_ `true` _if the binary tree is **Even-Odd** , otherwise return_ `false`_._
*
* **Example 1:**
*
* ![](https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png)
*
* **Input:** root = [1,10,4,3,null,7,9,12,8,6,null,null,2]
*
* **Output:** true
*
* **Explanation:** The node values on each level are:
*
* Level 0: [1]
*
* Level 1: [10,4]
*
* Level 2: [3,7,9]
*
* Level 3: [12,8,6,2]
*
* Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd.
*
* **Example 2:**
*
* ![](https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png)
*
* **Input:** root = [5,4,2,3,3,7]
*
* **Output:** false
*
* **Explanation:** The node values on each level are:
*
* Level 0: [5]
*
* Level 1: [4,2]
*
* Level 2: [3,3,7]
*
* Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd.
*
* **Example 3:**
*
* ![](https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png)
*
* **Input:** root = [5,9,1,3,5,7]
*
* **Output:** false
*
* **Explanation:** Node values in the level 1 should be even integers.
*
* **Constraints:**
*
* * The number of nodes in the tree is in the range [1, 105]
.
* * 1 <= Node.val <= 106
**/
public class Solution {
private final List comp = new ArrayList<>();
public boolean isEvenOddTree(TreeNode root) {
return find(root, 0);
}
private boolean find(TreeNode root, int height) {
if (root == null) {
return true;
}
if ((height % 2 == 0 && root.val % 2 == 0) || (height % 2 == 1 && root.val % 2 == 1)) {
return false;
}
if (comp.size() == height) {
comp.add(root.val);
} else {
if (height % 2 == 0) {
if (comp.get(height) >= root.val) {
return false;
} else {
comp.set(height, root.val);
}
} else {
if (comp.get(height) <= root.val) {
return false;
} else {
comp.set(height, root.val);
}
}
}
return find(root.left, height + 1) && find(root.right, height + 1);
}
}
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