g1601_1700.s1691_maximum_height_by_stacking_cuboids.Solution Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1601_1700.s1691_maximum_height_by_stacking_cuboids;
// #Hard #Array #Dynamic_Programming #Sorting #2022_04_15_Time_6_ms_(83.07%)_Space_42_MB_(80.25%)
import java.util.Arrays;
/**
* 1691 - Maximum Height by Stacking Cuboids\.
*
* Hard
*
* Given `n` `cuboids` where the dimensions of the ith
cuboid is cuboids[i] = [widthi, lengthi, heighti]
( **0-indexed** ). Choose a **subset** of `cuboids` and place them on each other.
*
* You can place cuboid `i` on cuboid `j` if widthi <= widthj
and lengthi <= lengthj
and heighti <= heightj
. You can rearrange any cuboid's dimensions by rotating it to put it on another cuboid.
*
* Return _the **maximum height** of the stacked_ `cuboids`.
*
* **Example 1:**
*
* **![](https://assets.leetcode.com/uploads/2019/10/21/image.jpg)**
*
* **Input:** cuboids = \[\[50,45,20],[95,37,53],[45,23,12]]
*
* **Output:** 190
*
* **Explanation:**
*
* Cuboid 1 is placed on the bottom with the 53x37 side facing down with height 95.
*
* Cuboid 0 is placed next with the 45x20 side facing down with height 50.
*
* Cuboid 2 is placed next with the 23x12 side facing down with height 45.
*
* The total height is 95 + 50 + 45 = 190.
*
* **Example 2:**
*
* **Input:** cuboids = \[\[38,25,45],[76,35,3]]
*
* **Output:** 76
*
* **Explanation:**
*
* You can't place any of the cuboids on the other.
*
* We choose cuboid 1 and rotate it so that the 35x3 side is facing down and its height is 76.
*
* **Example 3:**
*
* **Input:** cuboids = \[\[7,11,17],[7,17,11],[11,7,17],[11,17,7],[17,7,11],[17,11,7]]
*
* **Output:** 102
*
* **Explanation:**
*
* After rearranging the cuboids, you can see that all cuboids have the same dimension.
*
* You can place the 11x7 side down on all cuboids so their heights are 17.
*
* The maximum height of stacked cuboids is 6 \* 17 = 102.
*
* **Constraints:**
*
* * `n == cuboids.length`
* * `1 <= n <= 100`
* * 1 <= widthi, lengthi, heighti <= 100
**/
public class Solution {
public int maxHeight(int[][] arr) {
for (int[] a : arr) {
Arrays.sort(a);
}
Arrays.sort(
arr,
(a, b) -> {
if (a[0] != b[0]) {
return a[0] - b[0];
} else if (a[1] != b[1]) {
return a[1] - b[1];
}
return a[2] - b[2];
});
int ans = 0;
int[] dp = new int[arr.length];
for (int i = 0; i < arr.length; i++) {
dp[i] = arr[i][2];
for (int j = 0; j < i; j++) {
if (arr[i][0] >= arr[j][0] && arr[i][1] >= arr[j][1] && arr[i][2] >= arr[j][2]) {
dp[i] = Math.max(dp[i], arr[i][2] + dp[j]);
}
}
ans = Math.max(ans, dp[i]);
}
return ans;
}
}
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