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Java-based LeetCode algorithm problem solutions, regularly updated
package g2401_2500.s2453_destroy_sequential_targets;
// #Medium #Array #Hash_Table #Counting #2022_12_15_Time_33_ms_(96.27%)_Space_58.9_MB_(95.38%)
import java.util.HashMap;
/**
* 2453 - Destroy Sequential Targets\.
*
* Medium
*
* You are given a **0-indexed** array `nums` consisting of positive integers, representing targets on a number line. You are also given an integer `space`.
*
* You have a machine which can destroy targets. **Seeding** the machine with some `nums[i]` allows it to destroy all targets with values that can be represented as `nums[i] + c * space`, where `c` is any non-negative integer. You want to destroy the **maximum** number of targets in `nums`.
*
* Return _the **minimum value** of_ `nums[i]` _you can seed the machine with to destroy the maximum number of targets._
*
* **Example 1:**
*
* **Input:** nums = [3,7,8,1,1,5], space = 2
*
* **Output:** 1
*
* **Explanation:** If we seed the machine with nums[3], then we destroy all targets equal to 1,3,5,7,9,... In this case, we would destroy 5 total targets (all except for nums[2]). It is impossible to destroy more than 5 targets, so we return nums[3].
*
* **Example 2:**
*
* **Input:** nums = [1,3,5,2,4,6], space = 2
*
* **Output:** 1
*
* **Explanation:** Seeding the machine with nums[0], or nums[3] destroys 3 targets. It is not possible to destroy more than 3 targets. Since nums[0] is the minimal integer that can destroy 3 targets, we return 1.
*
* **Example 3:**
*
* **Input:** nums = [6,2,5], space = 100
*
* **Output:** 2
*
* **Explanation:** Whatever initial seed we select, we can only destroy 1 target. The minimal seed is nums[1].
*
* **Constraints:**
*
* * 1 <= nums.length <= 105
* * 1 <= nums[i] <= 109
* * 1 <= space <= 109
**/
public class Solution {
public int destroyTargets(int[] nums, int space) {
HashMap map = new HashMap<>();
for (int num : nums) {
int reminder = num % space;
int freq = map.getOrDefault(reminder, 0);
map.put(reminder, freq + 1);
}
int maxCount = 0;
int ans = Integer.MAX_VALUE;
for (int count : map.values()) {
maxCount = Math.max(count, maxCount);
}
for (int val : nums) {
if (map.get(val % space) == maxCount) {
ans = Math.min(ans, val);
}
}
return ans;
}
}
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