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Java-based LeetCode algorithm problem solutions, regularly updated
package g2701_2800.s2748_number_of_beautiful_pairs;
// #Easy #Array #Math #Number_Theory #2023_09_24_Time_11_ms_(91.00%)_Space_43.3_MB_(63.82%)
/**
* 2748 - Number of Beautiful Pairs\.
*
* Easy
*
* You are given a **0-indexed** integer array `nums`. A pair of indices `i`, `j` where `0 <= i < j < nums.length` is called beautiful if the **first digit** of `nums[i]` and the **last digit** of `nums[j]` are **coprime**.
*
* Return _the total number of beautiful pairs in_ `nums`.
*
* Two integers `x` and `y` are **coprime** if there is no integer greater than 1 that divides both of them. In other words, `x` and `y` are coprime if `gcd(x, y) == 1`, where `gcd(x, y)` is the **greatest common divisor** of `x` and `y`.
*
* **Example 1:**
*
* **Input:** nums = [2,5,1,4]
*
* **Output:** 5
*
* **Explanation:** There are 5 beautiful pairs in nums:
*
* When i = 0 and j = 1: the first digit of nums[0] is 2, and the last digit of nums[1] is 5. We can confirm that 2 and 5 are coprime, since gcd(2,5) == 1.
*
* When i = 0 and j = 2: the first digit of nums[0] is 2, and the last digit of nums[2] is 1. Indeed, gcd(2,1) == 1.
*
* When i = 1 and j = 2: the first digit of nums[1] is 5, and the last digit of nums[2] is 1. Indeed, gcd(5,1) == 1.
*
* When i = 1 and j = 3: the first digit of nums[1] is 5, and the last digit of nums[3] is 4. Indeed, gcd(5,4) == 1.
*
* When i = 2 and j = 3: the first digit of nums[2] is 1, and the last digit of nums[3] is 4. Indeed, gcd(1,4) == 1.
*
* Thus, we return 5.
*
* **Example 2:**
*
* **Input:** nums = [11,21,12]
*
* **Output:** 2
*
* **Explanation:** There are 2 beautiful pairs:
*
* When i = 0 and j = 1: the first digit of nums[0] is 1, and the last digit of nums[1] is 1. Indeed, gcd(1,1) == 1.
*
* When i = 0 and j = 2: the first digit of nums[0] is 1, and the last digit of nums[2] is 2. Indeed, gcd(1,2) == 1.
*
* Thus, we return 2.
*
* **Constraints:**
*
* * `2 <= nums.length <= 100`
* * `1 <= nums[i] <= 9999`
* * `nums[i] % 10 != 0`
**/
public class Solution {
public int countBeautifulPairs(int[] nums) {
int beautifulPairs = 0;
int i = 0;
int j = 1;
while (i < nums.length - 1) {
int firstDigit = getFirstDigit(nums[i]);
while (j < nums.length) {
int lastDigit = nums[j] % 10;
boolean botDigitsAreEqualAndNot1 = firstDigit == lastDigit && firstDigit > 1;
boolean botDigitsAreDivisibleBy2 = firstDigit % 2 == 0 && lastDigit % 2 == 0;
boolean botDigitsAreDivisibleBy3 = firstDigit % 3 == 0 && lastDigit % 3 == 0;
if (!botDigitsAreEqualAndNot1
&& !botDigitsAreDivisibleBy2
&& !botDigitsAreDivisibleBy3) {
beautifulPairs++;
}
j++;
}
i++;
j = i + 1;
}
return beautifulPairs;
}
private int getFirstDigit(int num) {
int n = num;
int digit = 0;
while (n > 0) {
digit = n % 10;
n /= 10;
}
return digit;
}
}
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