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g2401_2500.s2463_minimum_total_distance_traveled.readme.md Maven / Gradle / Ivy

2463\. Minimum Total Distance Traveled

Hard

There are some robots and factories on the X-axis. You are given an integer array `robot` where `robot[i]` is the position of the ith robot. You are also given a 2D integer array `factory` where factory[j] = [positionj, limitj] indicates that positionj is the position of the jth factory and that the jth factory can repair at most limitj robots.

The positions of each robot are **unique**. The positions of each factory are also **unique**. Note that a robot can be **in the same position** as a factory initially.

All the robots are initially broken; they keep moving in one direction. The direction could be the negative or the positive direction of the X-axis. When a robot reaches a factory that did not reach its limit, the factory repairs the robot, and it stops moving.

**At any moment**, you can set the initial direction of moving for **some** robot. Your target is to minimize the total distance traveled by all the robots.

Return _the minimum total distance traveled by all the robots_. The test cases are generated such that all the robots can be repaired.

**Note that**

*   All robots move at the same speed.
*   If two robots move in the same direction, they will never collide.
*   If two robots move in opposite directions and they meet at some point, they do not collide. They cross each other.
*   If a robot passes by a factory that reached its limits, it crosses it as if it does not exist.
*   If the robot moved from a position `x` to a position `y`, the distance it moved is `|y - x|`.

**Example 1:**

![](https://assets.leetcode.com/uploads/2022/09/15/example1.jpg)

**Input:** robot = [0,4,6], factory = [[2,2],[6,2]]

**Output:** 4

**Explanation:** As shown in the figure:

- The first robot at position 0 moves in the positive direction. It will be repaired at the first factory.

- The second robot at position 4 moves in the negative direction. It will be repaired at the first factory.

- The third robot at position 6 will be repaired at the second factory. It does not need to move.

The limit of the first factory is 2, and it fixed 2 robots.

The limit of the second factory is 2, and it fixed 1 robot.

The total distance is |2 - 0| + |2 - 4| + |6 - 6| = 4. It can be shown that we cannot achieve a better total distance than 4. 

**Example 2:**

![](https://assets.leetcode.com/uploads/2022/09/15/example-2.jpg)

**Input:** robot = [1,-1], factory = [[-2,1],[2,1]]

**Output:** 2

**Explanation:** As shown in the figure:

- The first robot at position 1 moves in the positive direction. It will be repaired at the second factory.

- The second robot at position -1 moves in the negative direction. It will be repaired at the first factory.

The limit of the first factory is 1, and it fixed 1 robot. The limit of the second factory is 1, and it fixed 1 robot.

The total distance is |2 - 1| + |(-2) - (-1)| = 2. It can be shown that we cannot achieve a better total distance than 2. 

**Constraints:**

*   `1 <= robot.length, factory.length <= 100`
*   `factory[j].length == 2`
*   -109 <= robot[i], positionj <= 109
*   0 <= limitj <= robot.length
*   The input will be generated such that it is always possible to repair every robot.