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Java-based LeetCode algorithm problem solutions, regularly updated
package g0101_0200.s0110_balanced_binary_tree;
// #Easy #Depth_First_Search #Tree #Binary_Tree #Programming_Skills_II_Day_2 #Level_2_Day_6_Tree
// #Udemy_Tree_Stack_Queue #2022_06_22_Time_1_ms_(98.82%)_Space_44.8_MB_(19.20%)
import com_github_leetcode.TreeNode;
/*
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) {
// Empty Tree is balanced
if (root == null) {
return true;
}
// Get max height of subtree child
// Get max height of subtree child
// compare height difference (cannot be more than 1)
int leftHeight = 0;
int rightHeight = 0;
if (root.left != null) {
leftHeight = getMaxHeight(root.left);
}
if (root.right != null) {
rightHeight = getMaxHeight(root.right);
}
int heightDiff = Math.abs(leftHeight - rightHeight);
// if passes height check
// - Check if left subtree is balanced and if the right subtree is balanced
// - If one of both are imbalanced, then the tree is imbalanced
return heightDiff <= 1 && isBalanced(root.left) && isBalanced(root.right);
}
private int getMaxHeight(TreeNode root) {
if (root == null) {
return 0;
}
int leftHeight = 0;
int rightHeight = 0;
// Left
if (root.left != null) {
leftHeight = getMaxHeight(root.left);
}
// Right
if (root.right != null) {
rightHeight = getMaxHeight(root.right);
}
if (leftHeight > rightHeight) {
return 1 + leftHeight;
} else {
return 1 + rightHeight;
}
}
}