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Java-based LeetCode algorithm problem solutions, regularly updated
package g0401_0500.s0427_construct_quad_tree;
// #Medium #Array #Tree #Matrix #Divide_and_Conquer
// #2022_07_16_Time_0_ms_(100.00%)_Space_42.6_MB_(89.45%)
/*
// Definition for a QuadTree node.
class Node {
public boolean val;
public boolean isLeaf;
public Node topLeft;
public Node topRight;
public Node bottomLeft;
public Node bottomRight;
public Node() {
this.val = false;
this.isLeaf = false;
this.topLeft = null;
this.topRight = null;
this.bottomLeft = null;
this.bottomRight = null;
}
public Node(boolean val, boolean isLeaf) {
this.val = val;
this.isLeaf = isLeaf;
this.topLeft = null;
this.topRight = null;
this.bottomLeft = null;
this.bottomRight = null;
}
public Node(boolean val, boolean isLeaf, Node topLeft, Node topRight, Node bottomLeft, Node bottomRight) {
this.val = val;
this.isLeaf = isLeaf;
this.topLeft = topLeft;
this.topRight = topRight;
this.bottomLeft = bottomLeft;
this.bottomRight = bottomRight;
}
};
*/
public class Solution {
public Node construct(int[][] grid) {
return optimizedDfs(grid, 0, 0, grid.length);
}
private Node optimizedDfs(int[][] grid, int rowStart, int colStart, int len) {
int zeroCount = 0;
int oneCount = 0;
for (int row = rowStart; row < rowStart + len; row++) {
boolean isBreak = false;
for (int col = colStart; col < colStart + len; col++) {
if (grid[row][col] == 0) {
zeroCount++;
} else {
oneCount++;
}
if (oneCount > 0 && zeroCount > 0) {
// We really no need to scan all.
// Once we know there are both 0 and 1 then we can break.
isBreak = true;
break;
}
}
if (isBreak) {
break;
}
}
if (oneCount > 0 && zeroCount > 0) {
int midLen = len / 2;
Node topLeft = optimizedDfs(grid, rowStart, colStart, midLen);
Node topRight = optimizedDfs(grid, rowStart, colStart + midLen, midLen);
Node bottomLeft = optimizedDfs(grid, rowStart + midLen, colStart, midLen);
Node bottomRight = optimizedDfs(grid, rowStart + midLen, colStart + midLen, midLen);
boolean isLeaf = false;
return new Node(true, isLeaf, topLeft, topRight, bottomLeft, bottomRight);
} else {
boolean resultVal = oneCount > 0;
boolean isLeaf = true;
return new Node(resultVal, isLeaf);
}
}
}