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g0601_0700.s0684_redundant_connection.readme.md Maven / Gradle / Ivy

684\. Redundant Connection

Medium

In this problem, a tree is an **undirected graph** that is connected and has no cycles.

You are given a graph that started as a tree with `n` nodes labeled from `1` to `n`, with one additional edge added. The added edge has two **different** vertices chosen from `1` to `n`, and was not an edge that already existed. The graph is represented as an array `edges` of length `n` where edges[i] = [ai, bi] indicates that there is an edge between nodes ai and bi in the graph.

Return _an edge that can be removed so that the resulting graph is a tree of_ `n` _nodes_. If there are multiple answers, return the answer that occurs last in the input.

**Example 1:**

![](https://assets.leetcode.com/uploads/2021/05/02/reduntant1-1-graph.jpg)

**Input:** edges = [[1,2],[1,3],[2,3]]

**Output:** [2,3]

**Example 2:**

![](https://assets.leetcode.com/uploads/2021/05/02/reduntant1-2-graph.jpg)

**Input:** edges = [[1,2],[2,3],[3,4],[1,4],[1,5]]

**Output:** [1,4]

**Constraints:**

*   `n == edges.length`
*   `3 <= n <= 1000`
*   `edges[i].length == 2`
*   1 <= ai < bi <= edges.length
*   ai != bi
*   There are no repeated edges.
*   The given graph is connected.