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Java-based LeetCode algorithm problem solutions, regularly updated
package g1001_1100.s1061_lexicographically_smallest_equivalent_string;
// #Medium #String #Union_Find #2023_06_09_Time_2_ms_(93.75%)_Space_41.7_MB_(41.30%)
public class Solution {
private int[] parent;
public String smallestEquivalentString(String s1, String s2, String baseStr) {
parent = new int[26];
int n = s1.length();
StringBuilder result = new StringBuilder();
for (int i = 0; i < 26; i++) {
parent[i] = i;
}
for (int i = 0; i < n; i++) {
union(s1.charAt(i) - 'a', s2.charAt(i) - 'a');
}
char base = 'a';
for (char element : baseStr.toCharArray()) {
result.append(Character.toString(base + find(element - 'a')));
}
return result.toString();
}
private void union(int a, int b) {
int parentA = find(a);
int parentB = find(b);
if (parentA != parentB) {
if (parentA < parentB) {
parent[parentB] = parentA;
} else {
parent[parentA] = parentB;
}
}
}
private int find(int x) {
while (parent[x] != x) {
x = parent[x];
}
return x;
}
}