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Java-based LeetCode algorithm problem solutions, regularly updated
package g1201_1300.s1202_smallest_string_with_swaps;
// #Medium #String #Hash_Table #Depth_First_Search #Breadth_First_Search #Union_Find
// #2022_03_08_Time_43_ms_(86.82%)_Space_94.1_MB_(64.69%)
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class Solution {
public String smallestStringWithSwaps(String s, List> pairs) {
UF uf = new UF(s.length());
for (List p : pairs) {
uf.union(p.get(0), p.get(1));
}
Map freqMapPerRoot = new HashMap<>();
for (int i = 0; i < s.length(); i++) {
freqMapPerRoot.computeIfAbsent(uf.find(i), x -> new int[26])[s.charAt(i) - 'a']++;
}
char[] ans = new char[s.length()];
for (int i = 0; i < ans.length; i++) {
int[] css = freqMapPerRoot.get(uf.find(i));
for (int j = 0; j < css.length; j++) {
if (css[j] > 0) {
ans[i] = (char) (j + 'a');
css[j]--;
break;
}
}
}
return new String(ans);
}
static class UF {
int[] root;
int[] rank;
UF(int n) {
root = new int[n];
rank = new int[n];
for (int i = 0; i < n; i++) {
root[i] = i;
rank[i] = 1;
}
}
int find(int u) {
if (u == root[u]) {
return u;
}
root[u] = find(root[u]);
return root[u];
}
void union(int u, int v) {
int ru = find(root[u]);
int rv = find(root[v]);
if (ru != rv) {
if (rank[ru] < rank[rv]) {
root[ru] = root[rv];
} else if (rank[ru] > rank[rv]) {
root[rv] = root[ru];
} else {
root[rv] = root[ru];
rank[ru]++;
}
}
}
}
}