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Java-based LeetCode algorithm problem solutions, regularly updated
1592\. Rearrange Spaces Between Words
Easy
You are given a string `text` of words that are placed among some number of spaces. Each word consists of one or more lowercase English letters and are separated by at least one space. It's guaranteed that `text` **contains at least one word**.
Rearrange the spaces so that there is an **equal** number of spaces between every pair of adjacent words and that number is **maximized**. If you cannot redistribute all the spaces equally, place the **extra spaces at the end**, meaning the returned string should be the same length as `text`.
Return _the string after rearranging the spaces_.
**Example 1:**
**Input:** text = " this is a sentence "
**Output:** "this is a sentence"
**Explanation:** There are a total of 9 spaces and 4 words. We can evenly divide the 9 spaces between the words: 9 / (4-1) = 3 spaces.
**Example 2:**
**Input:** text = " practice makes perfect"
**Output:** "practice makes perfect "
**Explanation:** There are a total of 7 spaces and 3 words. 7 / (3-1) = 3 spaces plus 1 extra space. We place this extra space at the end of the string.
**Constraints:**
* `1 <= text.length <= 100`
* `text` consists of lowercase English letters and `' '`.
* `text` contains at least one word.