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g1601_1700.s1646_get_maximum_in_generated_array.readme.md Maven / Gradle / Ivy

1646\. Get Maximum in Generated Array

Easy

You are given an integer `n`. A **0-indexed** integer array `nums` of length `n + 1` is generated in the following way:

*   `nums[0] = 0`
*   `nums[1] = 1`
*   `nums[2 * i] = nums[i]` when `2 <= 2 * i <= n`
*   `nums[2 * i + 1] = nums[i] + nums[i + 1]` when `2 <= 2 * i + 1 <= n`

Return _the **maximum** integer in the array_ `nums`.

**Example 1:**

**Input:** n = 7

**Output:** 3

**Explanation:** According to the given rules: 

nums[0] = 0 

nums[1] = 1

nums[(1 \* 2) = 2] = nums[1] = 1 

nums[(1 \* 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2 

nums[(2 \* 2) = 4] = nums[2] = 1 

nums[(2 \* 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3 

nums[(3 \* 2) = 6] = nums[3] = 2 

nums[(3 \* 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3 

Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is max(0,1,1,2,1,3,2,3) = 3.

**Example 2:**

**Input:** n = 2

**Output:** 1

**Explanation:** According to the given rules, nums = [0,1,1]. The maximum is max(0,1,1) = 1.

**Example 3:**

**Input:** n = 3

**Output:** 2

**Explanation:** According to the given rules, nums = [0,1,1,2]. The maximum is max(0,1,1,2) = 2.

**Constraints:**

*   `0 <= n <= 100`