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g1701_1800.s1705_maximum_number_of_eaten_apples.readme.md Maven / Gradle / Ivy

1705\. Maximum Number of Eaten Apples

Medium

There is a special kind of apple tree that grows apples every day for `n` days. On the ith day, the tree grows `apples[i]` apples that will rot after `days[i]` days, that is on day `i + days[i]` the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by `apples[i] == 0` and `days[i] == 0`.

You decided to eat **at most** one apple a day (to keep the doctors away). Note that you can keep eating after the first `n` days.

Given two integer arrays `days` and `apples` of length `n`, return _the maximum number of apples you can eat._

**Example 1:**

**Input:** apples = [1,2,3,5,2], days = [3,2,1,4,2]

**Output:** 7

**Explanation:** You can eat 7 apples:

- On the first day, you eat an apple that grew on the first day. 

- On the second day, you eat an apple that grew on the second day. 

- On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot.

- On the fourth to the seventh days, you eat apples that grew on the fourth day.

**Example 2:**

**Input:** apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2]

**Output:** 5

**Explanation:** You can eat 5 apples: 

- On the first to the third day you eat apples that grew on the first day. 

- Do nothing on the fouth and fifth days. 

- On the sixth and seventh days you eat apples that grew on the sixth day.

**Constraints:**

*   `n == apples.length == days.length`
*   1 <= n <= 2 * 104
*   0 <= apples[i], days[i] <= 2 * 104
*   `days[i] = 0` if and only if `apples[i] = 0`.