g1701_1800.s1728_cat_and_mouse_ii.Solution Maven / Gradle / Ivy
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Java-based LeetCode algorithm problem solutions, regularly updated
package g1701_1800.s1728_cat_and_mouse_ii;
// #Hard #Array #Dynamic_Programming #Math #Matrix #Graph #Memoization #Topological_Sort
// #Game_Theory #2022_04_28_Time_12_ms_(99.12%)_Space_42.7_MB_(96.49%)
import java.util.ArrayList;
import java.util.List;
@SuppressWarnings("unchecked")
public class Solution {
private static final int MOUSE_TURN = 0;
private final List[][] graphs = new List[2][];
private int foodPos;
private int[][][] memo;
public boolean canMouseWin(String[] grid, int catJump, int mouseJump) {
int m = grid.length;
int n = grid[0].length();
int mousePos = 0;
int catPos = 0;
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
char c = grid[i].charAt(j);
if (c == 'F') {
foodPos = i * n + j;
} else if (c == 'C') {
catPos = i * n + j;
} else if (c == 'M') {
mousePos = i * n + j;
}
}
}
graphs[0] = buildGraph(mouseJump, grid);
graphs[1] = buildGraph(catJump, grid);
memo = new int[m * n][m * n][2];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
char c = grid[i].charAt(j);
if (c == '#' || c == 'F') {
continue;
}
int catTurn = 1;
dfs(i * n + j, foodPos, catTurn);
}
}
return memo[mousePos][catPos][MOUSE_TURN] < 0;
}
private List[] buildGraph(int jump, String[] grid) {
int[][] dirs = {{-1, 0}, {1, 0}, {0, 1}, {0, -1}};
int m = grid.length;
int n = grid[0].length();
List[] graph = new List[m * n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
List list = new ArrayList<>();
graph[i * n + j] = list;
if (grid[i].charAt(j) == '#') {
continue;
}
list.add(i * n + j);
for (int[] dir : dirs) {
for (int step = 1; step <= jump; step++) {
int x = i + dir[0] * step;
int y = j + dir[1] * step;
if (x < 0 || x >= m || y < 0 || y >= n || grid[x].charAt(y) == '#') {
break;
}
list.add(x * n + y);
}
}
}
}
return graph;
}
private void dfs(int p1, int p2, int turn) {
if (p1 == p2) {
return;
}
if ((turn == 0 ? p2 : p1) == foodPos) {
return;
}
if (memo[p1][p2][turn] < 0) {
return;
}
memo[p1][p2][turn] = -1;
turn ^= 1;
for (int w : graphs[turn][p2]) {
if (turn == MOUSE_TURN || ++memo[w][p1][turn] == graphs[turn][w].size()) {
dfs(w, p1, turn);
}
}
}
}