g1701_1800.s1776_car_fleet_ii.readme.md Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-java21 Show documentation
Show all versions of leetcode-in-java21 Show documentation
Java-based LeetCode algorithm problem solutions, regularly updated
1776\. Car Fleet II
Hard
There are `n` cars traveling at different speeds in the same direction along a one-lane road. You are given an array `cars` of length `n`, where cars[i] = [positioni, speedi]
represents:
* positioni
is the distance between the ith
car and the beginning of the road in meters. It is guaranteed that positioni < positioni+1
.
* speedi
is the initial speed of the ith
car in meters per second.
For simplicity, cars can be considered as points moving along the number line. Two cars collide when they occupy the same position. Once a car collides with another car, they unite and form a single car fleet. The cars in the formed fleet will have the same position and the same speed, which is the initial speed of the **slowest** car in the fleet.
Return an array `answer`, where `answer[i]` is the time, in seconds, at which the ith
car collides with the next car, or `-1` if the car does not collide with the next car. Answers within 10-5
of the actual answers are accepted.
**Example 1:**
**Input:** cars = [[1,2],[2,1],[4,3],[7,2]]
**Output:** [1.00000,-1.00000,3.00000,-1.00000]
**Explanation:** After exactly one second, the first car will collide with the second car, and form a car fleet with speed 1 m/s. After exactly 3 seconds, the third car will collide with the fourth car, and form a car fleet with speed 2 m/s.
**Example 2:**
**Input:** cars = [[3,4],[5,4],[6,3],[9,1]]
**Output:** [2.00000,1.00000,1.50000,-1.00000]
**Constraints:**
* 1 <= cars.length <= 105
* 1 <= positioni, speedi <= 106
* positioni < positioni+1