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Java-based LeetCode algorithm problem solutions, regularly updated
package g1801_1900.s1882_process_tasks_using_servers;
// #Medium #Array #Heap_Priority_Queue #2022_05_06_Time_290_ms_(77.45%)_Space_69.1_MB_(95.62%)
import java.util.PriorityQueue;
public class Solution {
public int[] assignTasks(int[] servers, int[] tasks) {
PriorityQueue serverq =
new PriorityQueue<>(
(i1, i2) ->
servers[i1] != servers[i2] ? servers[i1] - servers[i2] : i1 - i2);
for (int i = 0; i < servers.length; i++) {
serverq.offer(i);
}
PriorityQueue activetaskq = new PriorityQueue<>((i1, i2) -> i1[1] - i2[1]);
int time = 0;
int[] res = new int[tasks.length];
for (int i = 0; i < tasks.length; i++) {
time = Math.max(time, i);
while (!activetaskq.isEmpty() && activetaskq.peek()[1] <= i) {
int[] task = activetaskq.poll();
serverq.offer(task[0]);
}
if (serverq.isEmpty()) {
int[] toptask = activetaskq.peek();
while (!activetaskq.isEmpty() && activetaskq.peek()[1] == toptask[1]) {
int[] task = activetaskq.poll();
serverq.offer(task[0]);
}
time = toptask[1];
}
int server = serverq.poll();
res[i] = server;
activetaskq.offer(new int[] {server, time + tasks[i]});
}
return res;
}
}