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Java-based LeetCode algorithm problem solutions, regularly updated
1898\. Maximum Number of Removable Characters
Medium
You are given two strings `s` and `p` where `p` is a **subsequence** of `s`. You are also given a **distinct 0-indexed** integer array `removable` containing a subset of indices of `s` (`s` is also **0-indexed**).
You want to choose an integer `k` (`0 <= k <= removable.length`) such that, after removing `k` characters from `s` using the **first** `k` indices in `removable`, `p` is still a **subsequence** of `s`. More formally, you will mark the character at `s[removable[i]]` for each `0 <= i < k`, then remove all marked characters and check if `p` is still a subsequence.
Return _the **maximum**_ `k` _you can choose such that_ `p` _is still a **subsequence** of_ `s` _after the removals_.
A **subsequence** of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
**Example 1:**
**Input:** s = "abcacb", p = "ab", removable = [3,1,0]
**Output:** 2
**Explanation:** After removing the characters at indices 3 and 1, "a**b**c**a**cb" becomes "accb".
"ab" is a subsequence of "**a**cc**b**".
If we remove the characters at indices 3, 1, and 0, "**ab**c**a**cb" becomes "ccb", and "ab" is no longer a subsequence.
Hence, the maximum k is 2.
**Example 2:**
**Input:** s = "abcbddddd", p = "abcd", removable = [3,2,1,4,5,6]
**Output:** 1
**Explanation:** After removing the character at index 3, "abc**b**ddddd" becomes "abcddddd".
"abcd" is a subsequence of "**abcd**dddd".
**Example 3:**
**Input:** s = "abcab", p = "abc", removable = [0,1,2,3,4]
**Output:** 0
**Explanation:** If you remove the first index in the array removable, "abc" is no longer a subsequence.
**Constraints:**
* 1 <= p.length <= s.length <= 105
* `0 <= removable.length < s.length`
* `0 <= removable[i] < s.length`
* `p` is a **subsequence** of `s`.
* `s` and `p` both consist of lowercase English letters.
* The elements in `removable` are **distinct**.