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Java-based LeetCode algorithm problem solutions, regularly updated
1995\. Count Special Quadruplets
Easy
Given a **0-indexed** integer array `nums`, return _the number of **distinct** quadruplets_ `(a, b, c, d)` _such that:_
* `nums[a] + nums[b] + nums[c] == nums[d]`, and
* `a < b < c < d`
**Example 1:**
**Input:** nums = [1,2,3,6]
**Output:** 1
**Explanation:** The only quadruplet that satisfies the requirement is (0, 1, 2, 3) because 1 + 2 + 3 == 6.
**Example 2:**
**Input:** nums = [3,3,6,4,5]
**Output:** 0
**Explanation:** There are no such quadruplets in [3,3,6,4,5].
**Example 3:**
**Input:** nums = [1,1,1,3,5]
**Output:** 4
**Explanation:** The 4 quadruplets that satisfy the requirement are:
- (0, 1, 2, 3): 1 + 1 + 1 == 3
- (0, 1, 3, 4): 1 + 1 + 3 == 5
- (0, 2, 3, 4): 1 + 1 + 3 == 5
- (1, 2, 3, 4): 1 + 1 + 3 == 5
**Constraints:**
* `4 <= nums.length <= 50`
* `1 <= nums[i] <= 100`