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Java-based LeetCode algorithm problem solutions, regularly updated
package g2001_2100.s2048_next_greater_numerically_balanced_number;
// #Medium #Math #Backtracking #Enumeration #2022_05_26_Time_2_ms_(95.19%)_Space_41.8_MB_(72.12%)
public class Solution {
public int nextBeautifulNumber(int n) {
int[] arr = new int[] {0, 1, 2, 3, 4, 5, 6};
boolean[] select = new boolean[7];
int d = n == 0 ? 1 : (int) Math.log10(n) + 1;
return solve(1, n, d, 0, select, arr);
}
private int solve(int i, int n, int d, int sz, boolean[] select, int[] arr) {
if (sz > d + 1) {
return Integer.MAX_VALUE;
}
if (i == select.length) {
return sz >= d ? make(0, n, sz, select, arr) : Integer.MAX_VALUE;
}
int ans = solve(i + 1, n, d, sz, select, arr);
select[i] = true;
ans = Math.min(ans, solve(i + 1, n, d, sz + i, select, arr));
select[i] = false;
return ans;
}
private int make(int cur, int n, int end, boolean[] select, int[] arr) {
if (end == 0) {
return cur > n ? cur : Integer.MAX_VALUE;
}
int ans = Integer.MAX_VALUE;
for (int j = 1; j < arr.length; j++) {
if (!select[j] || arr[j] == 0) {
continue;
}
--arr[j];
ans = Math.min(make(10 * cur + j, n, end - 1, select, arr), ans);
++arr[j];
}
return ans;
}
}