g2101_2200.s2122_recover_the_original_array.readme.md Maven / Gradle / Ivy
Go to download
Show more of this group Show more artifacts with this name
Show all versions of leetcode-in-java21 Show documentation
Show all versions of leetcode-in-java21 Show documentation
Java-based LeetCode algorithm problem solutions, regularly updated
2122\. Recover the Original Array
Hard
Alice had a **0-indexed** array `arr` consisting of `n` **positive** integers. She chose an arbitrary **positive integer** `k` and created two new **0-indexed** integer arrays `lower` and `higher` in the following manner:
1. `lower[i] = arr[i] - k`, for every index `i` where `0 <= i < n`
2. `higher[i] = arr[i] + k`, for every index `i` where `0 <= i < n`
Unfortunately, Alice lost all three arrays. However, she remembers the integers that were present in the arrays `lower` and `higher`, but not the array each integer belonged to. Help Alice and recover the original array.
Given an array `nums` consisting of `2n` integers, where **exactly** `n` of the integers were present in `lower` and the remaining in `higher`, return _the **original** array_ `arr`. In case the answer is not unique, return _**any** valid array_.
**Note:** The test cases are generated such that there exists **at least one** valid array `arr`.
**Example 1:**
**Input:** nums = [2,10,6,4,8,12]
**Output:** [3,7,11]
**Explanation:**
If arr = [3,7,11] and k = 1, we get lower = [2,6,10] and higher = [4,8,12].
Combining lower and higher gives us [2,6,10,4,8,12], which is a permutation of nums.
Another valid possibility is that arr = [5,7,9] and k = 3. In that case, lower = [2,4,6] and higher = [8,10,12].
**Example 2:**
**Input:** nums = [1,1,3,3]
**Output:** [2,2]
**Explanation:**
If arr = [2,2] and k = 1, we get lower = [1,1] and higher = [3,3].
Combining lower and higher gives us [1,1,3,3], which is equal to nums.
Note that arr cannot be [1,3] because in that case, the only possible way to obtain [1,1,3,3] is with k = 0.
This is invalid since k must be positive.
**Example 3:**
**Input:** nums = [5,435]
**Output:** [220]
**Explanation:** The only possible combination is arr = [220] and k = 215. Using them, we get lower = [5] and higher = [435].
**Constraints:**
* `2 * n == nums.length`
* `1 <= n <= 1000`
* 1 <= nums[i] <= 109
* The test cases are generated such that there exists **at least one** valid array `arr`.