• Home
• com.github.javadev
• leetcode-in-java21
• 1.30
• source code
• readme.md

×

Project download

Many resources are needed to download a project. Please understand that we have to compensate our server costs. Thank you in advance.
Project price only 1 $

You can buy this project and download/modify it how often you want.

g2201_2300.s2261_k_divisible_elements_subarrays.readme.md Maven / Gradle / Ivy

2261\. K Divisible Elements Subarrays

Medium

Given an integer array `nums` and two integers `k` and `p`, return _the number of **distinct subarrays** which have **at most**_ `k` _elements divisible by_ `p`.

Two arrays `nums1` and `nums2` are said to be **distinct** if:

*   They are of **different** lengths, or
*   There exists **at least** one index `i` where `nums1[i] != nums2[i]`.

A **subarray** is defined as a **non-empty** contiguous sequence of elements in an array.

**Example 1:**

**Input:** nums = [**2**,3,3,**2**,**2**], k = 2, p = 2

**Output:** 11

**Explanation:**

The elements at indices 0, 3, and 4 are divisible by p = 2.

The 11 distinct subarrays which have at most k = 2 elements divisible by 2 are:

[2], [2,3], [2,3,3], [2,3,3,2], [3], [3,3], [3,3,2], [3,3,2,2], [3,2], [3,2,2], and [2,2].

Note that the subarrays [2] and [3] occur more than once in nums, but they should each be counted only once.

The subarray [2,3,3,2,2] should not be counted because it has 3 elements that are divisible by 2.

**Example 2:**

**Input:** nums = [1,2,3,4], k = 4, p = 1

**Output:** 10

**Explanation:**

All element of nums are divisible by p = 1.

Also, every subarray of nums will have at most 4 elements that are divisible by 1.

Since all subarrays are distinct, the total number of subarrays satisfying all the constraints is 10.

**Constraints:**

*   `1 <= nums.length <= 200`
*   `1 <= nums[i], p <= 200`
*   `1 <= k <= nums.length`