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Java-based LeetCode algorithm problem solutions, regularly updated
2426\. Number of Pairs Satisfying Inequality
Hard
You are given two **0-indexed** integer arrays `nums1` and `nums2`, each of size `n`, and an integer `diff`. Find the number of **pairs** `(i, j)` such that:
* `0 <= i < j <= n - 1` **and**
* `nums1[i] - nums1[j] <= nums2[i] - nums2[j] + diff`.
Return _the **number of pairs** that satisfy the conditions._
**Example 1:**
**Input:** nums1 = [3,2,5], nums2 = [2,2,1], diff = 1
**Output:** 3
**Explanation:**
There are 3 pairs that satisfy the conditions:
1. i = 0, j = 1: 3 - 2 <= 2 - 2 + 1. Since i < j and 1 <= 1, this pair satisfies the conditions.
2. i = 0, j = 2: 3 - 5 <= 2 - 1 + 1. Since i < j and -2 <= 2, this pair satisfies the conditions.
3. i = 1, j = 2: 2 - 5 <= 2 - 1 + 1. Since i < j and -3 <= 2, this pair satisfies the conditions.
Therefore, we return 3.
**Example 2:**
**Input:** nums1 = [3,-1], nums2 = [-2,2], diff = -1
**Output:** 0
**Explanation:**
Since there does not exist any pair that satisfies the conditions, we return 0.
**Constraints:**
* `n == nums1.length == nums2.length`
* 2 <= n <= 105
* -104 <= nums1[i], nums2[i] <= 104
* -104 <= diff <= 104