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g2401_2500.s2430_maximum_deletions_on_a_string.readme.md Maven / Gradle / Ivy

2430\. Maximum Deletions on a String

Hard

You are given a string `s` consisting of only lowercase English letters. In one operation, you can:

*   Delete **the entire string** `s`, or
*   Delete the **first** `i` letters of `s` if the first `i` letters of `s` are **equal** to the following `i` letters in `s`, for any `i` in the range `1 <= i <= s.length / 2`.

For example, if `s = "ababc"`, then in one operation, you could delete the first two letters of `s` to get `"abc"`, since the first two letters of `s` and the following two letters of `s` are both equal to `"ab"`.

Return _the **maximum** number of operations needed to delete all of_ `s`.

**Example 1:**

**Input:** s = "abcabcdabc"

**Output:** 2

**Explanation:** 
- Delete the first 3 letters ("abc") since the next 3 letters are equal. Now, s = "abcdabc". 
 
- Delete all the letters. 

We used 2 operations so return 2. It can be proven that 2 is the maximum number of operations needed. 

Note that in the second operation we cannot delete "abc" again because the next occurrence of "abc" does not happen in the next 3 letters.

**Example 2:**

**Input:** s = "aaabaab"

**Output:** 4

**Explanation:** 
- 
- Delete the first letter ("a") since the next letter is equal. Now, s = "aabaab". 

- Delete the first 3 letters ("aab") since the next 3 letters are equal. Now, s = "aab". 

- Delete the first letter ("a") since the next letter is equal. Now, s = "ab".

- Delete all the letters. 

We used 4 operations so return 4. It can be proven that 4 is the maximum number of operations needed.

**Example 3:**

**Input:** s = "aaaaa"

**Output:** 5

**Explanation:** In each operation, we can delete the first letter of s.

**Constraints:**

*   `1 <= s.length <= 4000`
*   `s` consists only of lowercase English letters.