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Java-based LeetCode algorithm problem solutions, regularly updated
2707\. Extra Characters in a String
Medium
You are given a **0-indexed** string `s` and a dictionary of words `dictionary`. You have to break `s` into one or more **non-overlapping** substrings such that each substring is present in `dictionary`. There may be some **extra characters** in `s` which are not present in any of the substrings.
Return _the **minimum** number of extra characters left over if you break up_ `s` _optimally._
**Example 1:**
**Input:** s = "leetscode", dictionary = ["leet","code","leetcode"]
**Output:** 1
**Explanation:** We can break s in two substrings: "leet" from index 0 to 3 and "code" from index 5 to 8. There is only 1 unused character (at index 4), so we return 1.
**Example 2:**
**Input:** s = "sayhelloworld", dictionary = ["hello","world"]
**Output:** 3
**Explanation:** We can break s in two substrings: "hello" from index 3 to 7 and "world" from index 8 to 12. The characters at indices 0, 1, 2 are not used in any substring and thus are considered as extra characters. Hence, we return 3.
**Constraints:**
* `1 <= s.length <= 50`
* `1 <= dictionary.length <= 50`
* `1 <= dictionary[i].length <= 50`
* `dictionary[i]` and `s` consists of only lowercase English letters
* `dictionary` contains distinct words